Problem For Week Nine

Problem Nine (Jan 19th): Let V=R^n with standard orthorgonal basis \epsilon_1,\epsilon_2,\cdots,\epsilon_n, and define \Phi to be the set of all 2n(n-1) vectors \pm\epsilon_i\pm\epsilon_j, (1\leq i<j\leq n). Let W be the group generated by the 2n(n-1) reflections in R^4 sending \alpha = \pm\epsilon_i\pm\epsilon_j to its negative while fixing pointwise the hyperplane that is orthorgonal with \alpha. Prove that W is the semidirect product of the symmetric group S_n and \Bbb Z_2^{n-1}.

Solutions to last problem: p be a prime, and let \Bbb Z_p=\Bbb Z / p\Bbb Z denote the congruence classes in \Bbb Z modulo p. \Bbb Z_p^*=\Bbb Z_p-\{0\} also admits multiplication, making \Bbb Z_p a finite field.

Now we fix a n and define G_n=\{x^n:x\in \Bbb Z_p^*\}. Then G_n is a subgroup of \Bbb Z_p^*, and we can split \Bbb Z_p^* as coset space \Bbb Z_p^*=a_1G_n\cup a_2G_n\cup\cdots\cup a_rG_n.

Since z\to z^n is a surjective homomorphism from \Bbb Z_p^* to G_n, we have from the the fundamental theorem on homomorphisms that r is the number of solutions of the function x^n=1 in \Bbb Z_p^*.

When x \in a_i G_n, color x with i. This gives an r coloring of \Bbb Z_p^* = \{1, 2,\cdots, p - 1\}. If p-1 \geq S(n) \geq S(r), then by theorem 2 there is a monochromatic Schur triple, that is,  there are integers x, y, z, none of which is divisible by p, such that a_ix^n + a_iy^n \equiv a_iz^n \mod p, since a_i is not divisible by p it follows that  x_n + y_n = z_n \mod p, completing the proof.

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One Comment on “Problem For Week Nine”

  1. Anonymous Says:

    \text{Learn} \text{to} \text{use} \epsilon -\delta \text{language}, \text{and} \text{you} \text{will} \text{achieve} \text{more}.\text{See} \text{this} \text{equation}:\int x^x \, dx=\sum _{n=1}^{\infty } x^?


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